Solve inscribed angles (\(\theta_{\text{center}} = 2\theta_{\text{inscribed}}\)), cyclic quadrilaterals (opposite angles sum to \(180^\circ\)), intersecting chord segments (\(AP \cdot PB = CP \cdot PD\)), tangent-secant lengths, alternate segment angles, inside/outside intersection angles, and Gershgorin circle eigenvalue bounds.
Select theorem rule and enter geometric parameters.
Central Angle: 120.00° • θ_inscribed = 120.00° / 2 = 60.00°
| 📐 Solved Parameter | 60.00° |
| ⭕ Associated Angle / Value | Central Angle = 120.00° |
| 📜 Applied Theorem | Inscribed Angle Theorem |
| 🔢 Step-by-Step Proof | θ = 120.00° / 2 = 60.00° |
| 💡 Supplementary / Extra | Major Arc = 240.00° |
Euclidean circle theorems form the backbone of high school geometry (GCSE, IGCSE, SAT, AMC), surveying, celestial navigation, and structural engineering. However, identifying which theorem applies to intersecting lines, chords, or tangents can be challenging. Our Circle Theorems Calculator & Solver provides instant mathematical proof breakdowns:
Instantly verifies why the angle subtended at the center is always exactly twice the angle at the circumference (\(\theta_{\text{center}} = 2\theta_{\text{inscribed}}\)), and why Thales's semicircle angle is always an exact right angle (\(90^\circ\)).
Solves unknown chord lengths inside circles (\(AP \cdot PB = CP \cdot PD\)) and external tangent-secant lengths (\(PT^2 = PA \cdot PB\)) without drawing complex similar triangle proofs.
Computes opposite interior angles (\(\angle A + \angle C = 180^\circ\)) and exterior angles for 4-sided polygons inscribed in circles.
For advanced university mathematics and matrix eigenvalue bounds, calculates circular discs \(D(a_{ii}, R_i)\) in the complex plane where all matrix eigenvalues are guaranteed to reside.
Select from Inscribed Angles, Cyclic Quad, Chords, Tangent-Secant, Arc Angles, or Gershgorin.
Input given angle degrees (e.g. \(120^\circ\)) or line segment lengths (e.g. \(AP=6, PB=4, CP=8\)).
Review the exact mathematical derivation, applied geometric rule, and supplementary arc measurements.
Click Copy Circle Theorem Proof Card to copy a formatted proof report to your clipboard.
The angle subtended by an arc at the center is twice the angle subtended at the circumference: $$\theta_{\text{center}} = 2 \times \theta_{\text{inscribed}} \iff \theta_{\text{inscribed}} = \frac{\theta_{\text{center}}}{2}$$
An inscribed triangle whose base is the diameter always forms a right angle at the circumference: $$\theta_{\text{semicircle}} = 90^\circ$$
Inscribed angles subtended by the same arc (or chord) are always equal: $$\alpha = \beta = \gamma$$
Opposite interior angles of a cyclic quadrilateral always sum to \(180^\circ\) (supplementary): $$\angle A + \angle C = 180^\circ, \quad \angle B + \angle D = 180^\circ$$
A tangent line to a circle is perpendicular to the radius at the point of contact: $$\angle(\text{Radius}, \text{Tangent}) = 90^\circ$$
The angle between a tangent and a chord equals the inscribed angle in the alternate segment: $$\theta_{\text{tangent-chord}} = \theta_{\text{alternate}}$$
When two chords intersect inside a circle at point \(P\): $$AP \cdot PB = CP \cdot PD \implies PD = \frac{AP \cdot PB}{CP}$$
From external point \(P\), tangent \(PT\) and secant segments \(PA, PB\) satisfy: $$PT^2 = PA \cdot PB \implies PT = \sqrt{PA \cdot PB}$$
Consider circle with center \(O\) and chord \(AB\) subtending central angle \(\angle AOB\) and inscribed angle \(\angle APB\). Draw line segment from \(P\) through center \(O\). Triangles \(\triangle APO\) and \(\triangle BPO\) are isosceles because \(OA = OP = OB = r\) (circle radii).
• In \(\triangle APO\), base angles are equal: \(\angle OAP = \angle OPA = x\). By the exterior angle theorem, \(\angle AOX = 2x\).
• In \(\triangle BPO\), base angles are equal: \(\angle OBP = \angle OPB = y\). By the exterior angle theorem, \(\angle BOX = 2y\).
• Total inscribed angle is \(\angle APB = x + y\).
• Total central angle is \(\angle AOB = 2x + 2y = \mathbf{2(x + y)} = \mathbf{2 \times \angle APB}\). \(\quad \blacksquare\)
Draw line segments \(AC\) and \(DB\). In triangles \(\triangle APC\) and \(\triangle DPB\):
• \(\angle APC = \angle DPB\) (vertically opposite angles).
• \(\angle PAC = \angle PDB\) (angles subtended by the same arc \(CB\) in the same segment).
• By AA Similarity, \(\triangle APC \sim \triangle DPB\).
• Therefore, corresponding sides are in proportion: \(\frac{AP}{PD} = \frac{CP}{PB} \implies \mathbf{AP \cdot PB = CP \cdot PD}\). \(\quad \blacksquare\)
An arc subtends a central angle of \(110^\circ\). Find the angle subtended by this same arc at any point on the circumference.
Solution: \(\theta_{\text{inscribed}} = \frac{110^\circ}{2} = \mathbf{55.00^\circ}\) (Inscribed Angle Theorem).
Two chords intersect inside a circle at \(P\). If \(AP = 6\,\text{cm}\), \(PB = 4\,\text{cm}\), and \(CP = 8\,\text{cm}\), calculate the length of \(PD\).
Solution: \(AP \cdot PB = CP \cdot PD \implies 6 \times 4 = 8 \times PD \implies 24 = 8 \times PD \implies PD = \mathbf{3.00\,\text{cm}}\).
Two secants meet outside a circle. The far intercepted arc is \(110^\circ\) and the near arc is \(40^\circ\). Find the intersection angle.
Solution: \(\theta_{\text{outside}} = \frac{110^\circ - 40^\circ}{2} = \frac{70^\circ}{2} = \mathbf{35.00^\circ}\).
Comprehensive summary of Euclidean circle theorem formulas, inputs, and outputs.
| Theorem Name | Primary Formula | Sample Inputs | Calculated Result | Geometric Meaning |
|---|---|---|---|---|
| Inscribed Angle | \(\theta_i = \theta_c / 2\) | \(\theta_c = 120^\circ\) | \(\theta_i = 60^\circ\) | Center angle is 2x circumference |
| Thales Semicircle | \(\theta = 90^\circ\) | \(\theta_c = 180^\circ\) | \(\theta = 90^\circ\) | Right angle in semicircle |
| Cyclic Quad | \(\angle C = 180^\circ - \angle A\) | \(\angle A = 85^\circ\) | \(\angle C = 95^\circ\) | Opposite angles sum to 180° |
| Intersecting Chords | \(AP \cdot PB = CP \cdot PD\) | \(6, 4, 8\) | \(PD = 3.0\) | Internal segment products equal |
| Tangent-Secant | \(PT = \sqrt{PA \cdot PB}\) | \(PA=4, PB=16\) | \(PT = 8.0\) | Power of an external point |
| Outside Arc Angle | \(\theta = (\text{Arc}_1 - \text{Arc}_2)/2\) | \(110^\circ, 40^\circ\) | \(\theta = 35^\circ\) | Secant intersection exterior angle |
Authoritative answers to common questions about circle theorems, inscribed angles, cyclic quadrilaterals, chord segments, and Gershgorin discs.