Calculate circle surface area (\(A = \pi r^2 = \frac{\pi d^2}{4} = \frac{C^2}{4\pi}\)), radius, diameter, and circumference from any known dimension. Includes circular sector area, segment area, concentric ring annulus area, and pizza value comparison.
Select input dimension mode to calculate exact circle surface area.
Radius: 5.000 m • Diameter: 10.000 m • Circumference: 31.416 m
| 🍰 Circle Area (\(A\)) | 78.540 m² (πr²) |
| ⭕ Circle Radius (\(r\)) | 5.000 m |
| 📏 Circle Diameter (\(d\)) | 10.000 m (2r) |
| 🔄 Circumference (\(C\)) | 31.416 m (2πr) |
| 🍕 Sector Area (\(A_{\text{sector}}\)) | 13.090 m² |
| 📐 Segment Area (\(A_{\text{segment}}\)) | 2.265 m² |
| 🌓 Semicircle Area (\(A/2\)) | 39.270 m² |
| ⏹️ Inscribed Square Area | 50.000 m² (63.66%) |
| 🔲 Circumscribed Square Area | 100.000 m² (4r²) |
Determining circular surface area is essential in agricultural irrigation, landscaping, pizza economics, mechanical washer design, and civil engineering. Our Area of a Circle Calculator provides multidirectional analytical capabilities:
Solve for area directly whether you are given Radius (\(A = \pi r^2\)), Diameter (\(A = \frac{\pi d^2}{4}\)), or Circumference / Perimeter (\(A = \frac{C^2}{4\pi}\)) without requiring manual algebraic rearrangements.
Mechanical engineers can instantly calculate the surface contact area of metal washers and hollow cylindrical pipes using \(A = \pi(R^2 - r^2)\).
Because area scales with the square of diameter (\(A \propto d^2\)), a single 16-inch pizza delivers more total food surface (\(201.1\,\text{in}^2\)) than two 10-inch pizzas (\(157.1\,\text{in}^2\)).
Analyzes exact surface coverage ratios: an inscribed square occupies exactly \(\frac{2}{\pi} \approx 63.66\%\) of a circle's area, while a circle fills \(\frac{\pi}{4} \approx 78.54\%\) of its circumscribed square.
Select from Radius (\(r\)), Diameter (\(d\)), Circumference (\(C\)), or Annulus (\(R, r\)).
Type your measurement and select your desired metric or imperial unit (m, cm, mm, in, ft, yd).
Optionally adjust the central angle slider (\(\theta\)) to calculate pie slice sector and segment area.
Click Copy Area Telemetry Card to copy a formatted report for engineering CAD or homework.
$$A = \pi r^2 = \pi \left(\frac{d}{2}\right)^2 = \mathbf{\frac{\pi d^2}{4}} \approx 0.785398 \times d^2$$
$$r = \frac{C}{2\pi} \implies A = \pi \left(\frac{C}{2\pi}\right)^2 = \mathbf{\frac{C^2}{4\pi}} \approx \frac{C^2}{12.56637}$$
$$A_{\text{sector}} = \frac{\theta^\circ}{360^\circ}\pi r^2 = \frac{1}{2}r^2\theta_{\text{rad}} = \frac{1}{2}rs$$
$$A_{\text{annulus}} = \pi R^2 - \pi r^2 = \mathbf{\pi(R^2 - r^2)} = \pi(R - r)(R + r)$$
A circular helicopter landing pad has a diameter of \(d = 14.0\,\text{m}\). Find the total painted surface area.
Solution: \(r = 7.0\,\text{m}\). \(A = \pi(7.0^2) = 49\pi \approx \mathbf{153.938\,\text{m}^2}\) (or \(A = \frac{\pi(14^2)}{4} = \mathbf{153.938\,\text{m}^2}\)).
A circular race track has an outer perimeter fence measuring \(C = 500\,\text{m}\). What land area is enclosed?
Solution: \(A = \frac{C^2}{4\pi} = \frac{500^2}{4\pi} = \frac{250,000}{12.56637} \approx \mathbf{19,894.37\,\text{m}^2}\) (\(\approx 1.989\,\text{hectares}\)).
A steel circular pipe flange has outer radius \(R = 10.0\,\text{cm}\) and bolt bore inner radius \(r = 6.0\,\text{cm}\). Find the flange face surface area.
Solution: \(A_{\text{annulus}} = \pi(10^2 - 6^2) = \pi(100 - 36) = 64\pi \approx \mathbf{201.062\,\text{cm}^2}\).
Exact geometric dimensions from unit circles to planetary cross-sections.
| Object / Preset | Radius (\(r\)) | Diameter (\(d\)) | Circumference (\(C\)) | Circle Area (\(A\)) | Inscribed Square Area |
|---|---|---|---|---|---|
| Unit Circle | \(1.000\) | \(2.000\) | \(2\pi \approx 6.283\) | \(\pi \approx 3.142\) | \(2.000\) (\(63.66\%\)) |
| Compact Disc (CD) | \(60.00\,\text{mm}\) | \(120.00\,\text{mm}\) | \(376.99\,\text{mm}\) | \(113.10\,\text{cm}^2\) | \(72.00\,\text{cm}^2\) |
| Pizza 12" Medium | \(6.000\,\text{in}\) | \(12.000\,\text{in}\) | \(37.699\,\text{in}\) | \(113.10\,\text{in}^2\) | \(72.00\,\text{in}^2\) |
| Pizza 16" Large | \(8.000\,\text{in}\) | \(16.000\,\text{in}\) | \(50.265\,\text{in}\) | \(201.06\,\text{in}^2\) | \(128.00\,\text{in}^2\) |
| Olympic Archery Target | \(61.00\,\text{cm}\) | \(122.00\,\text{cm}\) | \(383.27\,\text{cm}\) | \(1.169\,\text{m}^2\) | \(0.744\,\text{m}^2\) |
| Basketball Rim | \(9.000\,\text{in}\) | \(18.000\,\text{in}\) | \(56.549\,\text{in}\) | \(254.47\,\text{in}^2\) | \(162.00\,\text{in}^2\) |
| Earth Cross-Section | \(6,378.1\,\text{km}\) | \(12,756.3\,\text{km}\) | \(40,075\,\text{km}\) | \(1.278 \times 10^8\,\text{km}^2\) | \(8.136 \times 10^7\,\text{km}^2\) |
Authoritative answers to common questions about circle area formulas, diameter calculations, sector areas, and annulus geometry.