100% Free • Circular Sector, Arc Length & Perimeter Solver

Sector Area Calculator

Calculate the area of a sector of a circle (\(A = \frac{\theta}{360^\circ}\pi r^2 = \frac{1}{2}r^2\alpha = \frac{1}{2}rL\)), arc length (\(L = \frac{\pi r\theta}{180^\circ}\)), closed perimeter (\(P = L + 2r\)), chord length (\(c = 2r\sin(\theta/2)\)), circular segment area, and sector centroid distance across degrees and radians.

Sector Presets: Tap to load

Sector Parameters

Select input combination to calculate sector area, perimeter, and arc geometry.

A = (θ/360°)πr² = ½rL
Given Parameters
Angle Measurement Unit
Radius (r)
Central Angle (θ)
°
Key Dimension Glance
Sector Area (A) 78.540 cm²
Arc Length (L) 15.708 cm
Closed Perimeter 35.708 cm
Circle Fraction 25.00%
Geometric Telemetry Matrix
📏 Circle Radius (\(r\)) 10.000 cm
📏 Circle Diameter (\(d\)) 20.000 cm
📐 Central Angle (\(\theta\)) 90.000° (1.571 rad)
🔄 Curved Arc Length (\(L\)) 15.708 cm
📏 Closed Perimeter (\(P\)) 35.708 cm (L + 2r)
🔵 Sector Area (\(A_{\text{sector}}\)) 78.540 cm²
🍕 Circle Coverage Fraction 25.000% (1/4 of circle)
📐 Chord Length (\(c\)) 14.142 cm (2r sin(θ/2))
📏 Sagitta Height (\(h\)) 2.929 cm
🔺 Triangle Area under Chord 50.000 cm² (½r² sin θ)
🌘 Circular Segment Area 28.540 cm² (A_sec - A_tri)
🎯 Centroid Distance (\(\bar{x}\)) 6.002 cm (from center)

Why Use Our Sector Area Calculator? Real-World Problems It Solves

Circular sectors (pie-shaped portions of a circle) are integral to civil highway curve design, agricultural center-pivot irrigation coverage, wind turbine swept areas, architectural arches, and culinary portion sizing. Our Sector Area Calculator solves critical real-world challenges:

1. Agricultural Sprinkler Irrigation Zones:

Calculates exact field acreage watered by rotating sprinkler heads covering partial arcs (\(90^\circ\), \(180^\circ\), or \(270^\circ\)) using \(A = \left(\frac{\theta}{360^\circ}\right)\pi r^2\).

2. Civil Engineering Highway Curves:

Computes arc length (\(L = \frac{\pi r\theta}{180^\circ}\)), chord length (\(c = 2r\sin(\theta/2)\)), and sightline sagitta clearances for horizontal road curves and railway tracks.

3. Circular Segment & Triangle Decomposition:

Decomposes any circular sector into its inner triangle area (\(\frac{1}{2}r^2\sin\theta\)) and outer circular segment region (\(A_{\text{seg}} = A_{\text{sec}} - A_{\text{tri}}\)).

4. Multidirectional Inverse Solving:

Solves for radius (\(r\)), central angle (\(\theta\)), arc length (\(L\)), or sector area (\(A\)) from any pair of given dimensions with seamless degree-to-radian conversions.

How to Calculate the Area and Perimeter of a Circular Sector (Step-by-Step Guide)

Step 1: Choose Given Inputs

Select from Radius & Angle, Radius & Arc Length, Arc & Angle, Area & Radius, or Area & Angle.

Step 2: Choose Angle Unit

Toggle between Degrees (°) and Radians (rad), and enter your numerical values.

Step 3: Review Sector Geometry

Inspect calculated sector area, arc length, perimeter, chord, and segment dimensions.

Step 4: Copy Full Telemetry

Click Copy Sector Telemetry Card to export formatted results for engineering, CAD, or homework.

All Circular Sector Formulas & Equations

1. Central Angle in Degrees (\(\theta\))

$$A_{\text{sector}} = \frac{\theta}{360^\circ} \times \pi r^2$$ $$L_{\text{arc}} = \frac{\theta}{360^\circ} \times 2\pi r = \frac{\pi r \theta}{180^\circ}$$ $$P_{\text{sector}} = L_{\text{arc}} + 2r = r\left(\frac{\pi \theta}{180^\circ} + 2\right)$$

2. Central Angle in Radians (\(\alpha\))

$$A_{\text{sector}} = \frac{1}{2} r^2 \alpha = \frac{1}{2} r L_{\text{arc}}$$ $$L_{\text{arc}} = r \alpha, \quad P = r(\alpha + 2)$$ $$\text{Relation: } A = \frac{L_{\text{arc}}^2}{2\alpha}$$

3. Chord, Sagitta & Segment Formulas

$$c = 2r \sin\left(\frac{\theta}{2}\right), \quad h_{\text{sagitta}} = r\left(1 - \cos\left(\frac{\theta}{2}\right)\right)$$ $$A_{\text{triangle}} = \frac{1}{2}r^2 \sin(\theta)$$ $$A_{\text{segment}} = A_{\text{sector}} - A_{\text{triangle}} = \frac{1}{2}r^2(\alpha - \sin\alpha)$$

4. Sector Centroid Distance (\(\bar{x}\))

$$\bar{x} = \frac{2r \sin(\alpha/2)}{3(\alpha/2)} = \frac{4r \sin(\theta/2)}{3\alpha_{\text{rad}}}$$ $$\text{Quadrant } (90^\circ): \bar{x} = \frac{4\sqrt{2}r}{3\pi} \approx 0.6002 \cdot r$$

Common Mistakes in Sector Calculations & How to Avoid Them

Mistake 1: Confusing Arc Length with Sector Perimeter

Arc length (\(L\)) only measures the curved outer edge of the sector. A closed sector includes the two straight radii borders: \(P = L + 2r\).

Mistake 2: Mixing Up Degree and Radian Formulas

Using \(\frac{1}{2}r^2\theta\) with \(\theta\) in degrees gives wildly incorrect answers! The formula \(\frac{1}{2}r^2\alpha\) requires angle \(\alpha\) in radians. For degrees, you must use \(\frac{\theta}{360^\circ}\pi r^2\).

Mistake 3: Confusing a Sector with a Segment

A circular sector is a pie slice connected to the circle center. A circular segment is only the outer slice between the chord and the arc. Segment Area = Sector Area − Triangle Area.

Mistake 4: Minor vs Major Sector Angles

If asked for the area of a shaded major sector with acute angle \(\theta\), the major sector angle is \(360^\circ - \theta\). Always ensure you are calculating the intended shaded region.

Classroom Practice & Study Guide: Sector Area Problems

Worked Practice Problems with Solutions:
Problem 1: Finding Sector Area & Perimeter from Radius and Angle

A circular sector has a radius of \(r = 12.0\,\text{cm}\) and a central angle of \(\theta = 60^\circ\). Calculate its area, arc length, and closed perimeter.

Solution: Sector Area: \(A = \frac{60}{360} \times \pi \times 12^2 = \frac{1}{6} \times 144\pi = 24\pi \approx \mathbf{75.398\,\text{cm}^2}\). Arc Length: \(L = \frac{60}{360} \times 2\pi(12) = 4\pi \approx \mathbf{12.566\,\text{cm}}\). Closed Perimeter: \(P = 12.566 + 2(12) = \mathbf{36.566\,\text{cm}}\).

Problem 2: Finding Central Angle from Known Sector Area

A circle of radius \(r = 8\,\text{m}\) has a shaded sector with area \(A = 50\,\text{m}^2\). What is the central angle in degrees and radians?

Solution: In radians: \(\alpha = \frac{2A}{r^2} = \frac{100}{64} = \mathbf{1.5625\,\text{rad}}\). In degrees: \(\theta = 1.5625 \times \frac{180^\circ}{\pi} \approx \mathbf{89.525^\circ}\).

Problem 3: Calculating Circular Segment Area

Find the area of the circular segment formed by a \(90^\circ\) sector of radius \(r = 10\,\text{cm}\).

Solution: Sector Area: \(A_{\text{sector}} = \frac{90}{360}\pi(10^2) = 25\pi \approx \mathbf{78.540\,\text{cm}^2}\). Triangle Area: \(A_{\text{tri}} = \frac{1}{2}(10)(10)\sin(90^\circ) = \mathbf{50.000\,\text{cm}^2}\). Segment Area: \(A_{\text{seg}} = 78.540 - 50 = \mathbf{28.540\,\text{cm}^2}\).

Master Benchmark Sector Geometry Matrix Table

Standard dimensions across canonical central angles for a circle of radius \(r = 10\,\text{cm}\).

Sector Benchmarks
Central Angle (\(\theta\)) Radians (\(\alpha\)) Sector Area (\(r=10\)) Arc Length (\(L\)) Chord Length (\(c\)) Circle Fraction
\(30^\circ\) (1/12th Circle) \(0.524\,\text{rad}\) (\(\frac{\pi}{6}\)) \(26.180\,\text{cm}^2\) \(5.236\,\text{cm}\) \(5.176\,\text{cm}\) \(8.33\%\)
\(45^\circ\) (Octant / 1/8th) \(0.785\,\text{rad}\) (\(\frac{\pi}{4}\)) \(39.270\,\text{cm}^2\) \(7.854\,\text{cm}\) \(7.654\,\text{cm}\) \(12.50\%\)
\(60^\circ\) (Sextant / 1/6th) \(1.047\,\text{rad}\) (\(\frac{\pi}{3}\)) \(52.360\,\text{cm}^2\) \(10.472\,\text{cm}\) \(10.000\,\text{cm}\) \(16.67\%\)
\(90^\circ\) (Quadrant / 1/4th) \(1.571\,\text{rad}\) (\(\frac{\pi}{2}\)) \(78.540\,\text{cm}^2\) \(15.708\,\text{cm}\) \(14.142\,\text{cm}\) \(25.00\%\)
\(180^\circ\) (Semicircle / 1/2) \(3.142\,\text{rad}\) (\(\pi\)) \(157.080\,\text{cm}^2\) \(31.416\,\text{cm}\) \(20.000\,\text{cm}\) \(50.00\%\)
\(270^\circ\) (Major 3/4th) \(4.712\,\text{rad}\) (\(\frac{3\pi}{2}\)) \(235.619\,\text{cm}^2\) \(47.124\,\text{cm}\) \(14.142\,\text{cm}\) \(75.00\%\)

Real-World Engineering, Agriculture & Design Applications

Everyday Engineering Implementations:
  • Center-Pivot Crop Irrigation: Calculating acreage irrigated by partial-swing water pivots on agricultural land.
  • Civil Road Design & Sightlines: Determining the curved distance (\(L\)) and lateral stopping sight distance (sagitta \(h\)) on highway curves.
  • Wind Turbine & Propeller Swept Area: Modeling airflow capture through partial rotor blade sectors.
  • Rotary Mechanical Cams & Gears: Sizing partial gear teeth arcs and sector-shaped counterweights.

Frequently Asked Questions (FAQ)

Authoritative answers to common questions about circular sector areas, arc lengths, perimeters, chord lengths, and segment calculations.